![]() same no of elements, values and in different order If we are concerned about the order of elements in an Array, we can use strict mode. We know that Lenient mode allows extensibility, but it has no effect on Array type. Unexpected elements "Mukesh", "Swati", and "Animesh" appear in the second Array.Īrray comparing the number of two different elements Other elements "Amod" and "Mukesh" are the same. "Ravi" is expected to be found in the second Array, but not found. ![]() The default is case sensitive, so the result is FAILĬompare two Arrays with the same number of elements but different element order // Same no of elements but different orderīecause Lenient mode is used, the order of elements is not affected, so the result is PASSĬompare Arrays with two elements with different values // Same no of elements but all different valuesĪs can be seen from the result output, first select elements from the first Array and try to find these elements in the second Array, not in order. JsonArray2 = "" īecause there are different values, the result must FAILĬompare two Arrays with the same number of elements and different value case // Same no of elements but different case values JSONAssert.assertEquals(jsonArray1, jsonArray2, JSONCompareMode.LENIENT) īecause the two array elements have the same number, values and order, the comparison result is PASSĬompare two Arrays with the same number of elements and different values // Same no of elements but different values We use examples to compare two Arrays in Lenient mode.Ĭompare two Arrays with the same elements, the same values and the same order // same no of elements, values and in same order JSONassert provides many statically overloaded assertEquals() methodsĪhead article We have learned that in Lenient mode, extensibility is allowed without strict sequence requirements. Please read the following articles to understand the basic concepts of JSON assert Java library, different comparison modes and assertion JSON Objects.Ĭompare JSON Objects Using JSONassert Library assertEquals() method There are many good Java libraries that can be used for comparison, as we mentioned earlier Comparing two JSONs with Jackson Library In this article, we mainly know how to use the JSONassert library to compare two JSON response s. For example, if we want to return the same result from an API every time, or part of the response body result is unchanged, we can directly compare the existing JSON response s, eliminating the need to write a lot of logic code to assert. Implement thread.REST Assured series summary REST Assured 71 - Compare JSON Arrays Using JSONassert Library introduceĪPI testing, sometimes you need to compare two JSON.Data Science vs Big Data vs Data Analytics.If we apply this function to a and b, the results compare equal: > ordered(a) = ordered(b) Return sorted((k, ordered(v)) for k, v in obj.items()) To fix that, we can define an ordered function which will recursively sort any lists it finds (and convert dictionaries to lists of (key, value) pairs so that they're orderable): def ordered(obj): ![]() ![]() """) > sorted(a.items()) = sorted(b.items())īut that doesn't work, because in each case, the "errors" item of the top-level dict is a list with the same elements in a different order, and sorted() doesn't try to sort anything except the "top" level of an iterable. Hello you want two objects with the same elements, but in a different order to compare equal, then the obvious thing to do is compare sorted copies of them - for instance, for the dictionaries represented by your JSON strings a and b: import json
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